Answer
$(-\infty,-1)\cup(2,\infty)$
Work Step by Step
$|1-2x|\gt3$, so $1-2x\gt3$ or $1-2x\lt-3$,
so $-2x\gt2$ or $-2x\lt-4$,
so $x\lt-1$ or $x\gt2$ thus the solution set is $(-\infty,-1)\cup(2,\infty)$
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