College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 45


The solution set is {$x|x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$}.

Work Step by Step

$|2x-3|\geq2$ $2x-3\geq2$ or $2x-3\leq-2$ Add 3 to both sides $2x\geq2+3$ or $2x\leq-2+3$ $2x\geq5$ or $2x\leq1$ Divide both sides by 2 $x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$ The solution set is {$x|x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$}
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