College Algebra (10th Edition)

The solution set is {$x|x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$}.
$|2x-3|\geq2$ $2x-3\geq2$ or $2x-3\leq-2$ Add 3 to both sides $2x\geq2+3$ or $2x\leq-2+3$ $2x\geq5$ or $2x\leq1$ Divide both sides by 2 $x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$ The solution set is {$x|x\geq\frac{5}{2}$ or $x\leq\frac{1}{2}$}