## College Algebra (10th Edition)

The solution set is {$x| x\geq-1$ or $x\leq-3$}.
$|-x-2|\geq1$ Solve absolute value. $-x-2\geq1$ or $-x-2\leq-1$ $-x-2+2\geq1+2$ or $-x-2+2\leq-1+2$ Add 2 to both sides of each inequality. $-x\geq3$ or $-x\leq1$ $\frac{-x}{-1}\leq\frac{3}{-1}$ or $\frac{-x} {-1}\geq\frac{1}{-1}$ Divide by -1 and reverse the inequality symbol. $x\leq-3$ or $x\geq-1$ The solution set is {$x| x\geq-1$ or $x\leq-3$}.