College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.6 - Equations and Inequalities Involving Absolute Value - 1.6 Assess Your Understanding - Page 133: 54


The solution set is {$x| x\geq-1$ or $x\leq-3$}.

Work Step by Step

$|-x-2|\geq1$ Solve absolute value. $-x-2\geq1$ or $-x-2\leq-1$ $-x-2+2\geq1+2$ or $-x-2+2\leq-1+2$ Add 2 to both sides of each inequality. $-x\geq3$ or $-x\leq1$ $\frac{-x}{-1}\leq\frac{3}{-1}$ or $\frac{-x} {-1}\geq\frac{1}{-1}$ Divide by -1 and reverse the inequality symbol. $x\leq-3$ or $x\geq-1$ The solution set is {$x| x\geq-1$ or $x\leq-3$}.
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