Answer
The solution set is {$-\frac{36}{5}, \frac{24}{5}$}
Work Step by Step
$|\frac{x}{3}+\frac{2}{5}|=2$
$\frac{x}{3}+\frac{2}{5}=2$ or $\frac{x}{3}+\frac{2}{5}=-2$
$\frac{x}{3}=2-\frac{2}{5}$ or $\frac{x}{3}=-2-\frac{2}{5}$
$\frac{x}{3}=\frac{10-2}{5}$ or $\frac{x}{3}=\frac{-10-2}{5}$
$\frac{x}{3}=\frac{8}{5}$ or $\frac{x}{3}=-\frac{12}{5}$
$x=\frac{8}{5}\cdot3$ or $x=-\frac{12}{5}\cdot3$
$x=\frac{24}{5}$ or $x=-\frac{36}{5}$
The solution set is {$-\frac{36}{5}, \frac{24}{5}$}