College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding: 81

Answer

$x=-1$ or $x=1$

Work Step by Step

We solve by factoring with grouping: $x^{3}+x^{2}-x-1=0$ $x^{2}(x+1)-1(x+1)=0$ $(x+1)(x^{2}-1)=0$ $(x+1)(x-1)(x+1)=0$ $x+1=0$ or $x-1=0$ or $x+1=0$ $x=-1$ or $x=1$
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