Answer
$x=0$ or $x=\frac{3}{4}$
Work Step by Step
We solve by factoring:
$4x^{3}=3x^{2}$
$4x^{3}-3x^{2}=0$
$x^{2}(4x-3)=0$
$x^{2}=0$ or $4x-3=0$
$x=\pm\sqrt{0}$ or $4x=3$
$x=0$ or $x=\frac{3}{4}$
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