College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 52

Answer

$x=7$ or $x=-2$

Work Step by Step

We solve by factoring: $(2-x)^{2}+(2-x)-20=0$ $[(2-x)+5][(2-x)-4]=0$ $(7-x)(-2-x)=0$ $7-x=0$ or $-2-x=0$ $x=7$ or $x=-2$
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