Answer
$x=7$ or $x=-2$
Work Step by Step
We solve by factoring:
$(2-x)^{2}+(2-x)-20=0$
$[(2-x)+5][(2-x)-4]=0$
$(7-x)(-2-x)=0$
$7-x=0$ or $-2-x=0$
$x=7$ or $x=-2$
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