Answer
$x=-1$ or $x=-\displaystyle \frac{7}{2}$
Work Step by Step
We solve by factoring:
$(2x+5)^{2}-(2x+5)-6=0$
$[(2x+5)-3][(2x+5)+2]=0$
$(2x+2)(2x+7)=0$
$(2x+2)=0$ or $(2x+7)=0$
$x=-1$ or $x=-\displaystyle \frac{7}{2}$
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