College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 55


$x=0$ or $x=\frac{1}{16}$

Work Step by Step

We solve by factoring: $x-4x\sqrt{x}=0$ $x(1-4\sqrt{x})=0$ $x=0$ or $1-4\sqrt{x}=0$ $x=0$ or $1=4\sqrt{x}$ $x=0$ or $\frac{1}{4}=\sqrt{x}$ $x=0$ or $(\frac{1}{4})^{2}=(\sqrt{x})^{2}$ $x=0$ or $x=\frac{1}{16}$
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