College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 54


$y=2$ or $y=\frac{5}{3}$.

Work Step by Step

$3(1-y)^2+5(1-y)+2=0\\3(1+y^2-2y)+5-5y+2=0\\3+3y^2-6y+7-5y=0\\3y^2-11y+10=0\\3y^2-5y-6y+10=y(3y-5)-2(3y-5)=(y-2)(3y-5)=0$ Thus $y=2$ or $y=\frac{5}{3}$. Check: $3\cdot(-1)^2+5\cdot(-1)+2=3-5+2=0$, $3\cdot(-2/3)^2+5\cdot(-2/3)+2=4/3-10/3+2=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.