Answer
$x=-5$ or $x=-6$
Work Step by Step
We solve by factoring:
$(x+2)^{2}+7(x+2)+12=0$
$[(x+2)+3][(x+2)+4]=0$
$(x+5)(x+6)=0$
$(x+5)=0$ or $(x+6)=0$
$x=-5$ or $x=-6$
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