College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 49


$x=-5$ or $x=-6$

Work Step by Step

We solve by factoring: $(x+2)^{2}+7(x+2)+12=0$ $[(x+2)+3][(x+2)+4]=0$ $(x+5)(x+6)=0$ $(x+5)=0$ or $(x+6)=0$ $x=-5$ or $x=-6$
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