Answer
$x=0$ or $x=-5$ or $x=4$
Work Step by Step
We solve by factoring:
$x^{3}+x^{2}-20x=0$
$x(x^{2}+x-20)=0$
$x(x+5)(x-4)=0$
$x=0$ or $x+5=0$ or $x-4=0$
$x=0$ or $x=-5$ or $x=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 79
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