Answer
$\displaystyle x=-\frac{1}{3}$
Work Step by Step
We solve by factoring:
$(3x+4)^{2}-6(3x+4)+9=0$
$[(3x+4)-3][(3x+4)-3]=0$
$(3x+1)^2=0$
$3x+1=0$
$x=-\frac{1}{3}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 51
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