Answer
$x=\pm\sqrt{97}$
Work Step by Step
We solve:
$(x^{2}-16)^{1/2}=9$
$[(x^{2}-16)^{1/2}]^{2}=9^{2}$
$x^{2}-16=81$
$x^{2}=97$
$x=\pm\sqrt{97}$
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