Answer
$x=0$ or $x=-7$ or $x=1$
Work Step by Step
We solve by factoring:
$x^{3}+6x^{2}-7x=0$
$x(x^{2}+6x-7)=0$
$x(x+7)(x-1)=0$
$x=0$ or $x+7=0$ or $x-1=0$
$x=0$ or $x=-7$ or $x=1$
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