College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 78

Answer

$x=0$ or $x=2$ or $x=-2$

Work Step by Step

We solve by factoring: $x^{5}=4x^{3}$ $x^{5}-4x^{3}=0$ $x^{3}(x^{2}-4)=0$ $x^{3}(x-2)(x+2)=0$ $x^{3}=0$ or $x-2=0$ or $x+2=0$ $x=0$ or $x=2$ or $x=-2$
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