Answer
$x=0$ or $x=2$ or $x=-2$
Work Step by Step
We solve by factoring:
$x^{5}=4x^{3}$
$x^{5}-4x^{3}=0$
$x^{3}(x^{2}-4)=0$
$x^{3}(x-2)(x+2)=0$
$x^{3}=0$ or $x-2=0$ or $x+2=0$
$x=0$ or $x=2$ or $x=-2$
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