Answer
$x=0$ or $x=1$ or $x=-1$
Work Step by Step
We solve by factoring:
$x^{4}-x^{2}=0$
$x^{2}(x^{2}-1)=0$
$x^{2}(x-1)(x+1)=0$
$x^{2}=0$ or $x-1=0$ or $x+1=0$
$x=\pm \sqrt{0}$ or $x=1$ or $x=-1$
$x=0$ or $x=1$ or $x=-1$
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