Answer
$x=16$ or $x=1$
Work Step by Step
We solve by factoring:
$x^{1/2}-3x^{1/4}+2=0$
$[x^{1/4}-2][x^{1/4}-1]=0$
$x^{1/4}-2=0$ or $x^{1/4}-1=0$
$x^{1/4}=2$ or $x^{1/4}=1$
$x=2^4$ or $x=1^4$
$x=16$ or $x=1$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 62
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