Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 48

Answer

(14)(6)

Work Step by Step

Given the number 84 we find two numbers that are perfect squares that add to give 84. We get +100 and -16 100 - 16 *** Take the square root of 100 which is 10. Becuase 10 × 10 = 100 *** Take the square root of 16 which is 4. Becuase 4 × 4 = 16 We rewrite it as the squares. $10^{2}$ - $4^{2}$ We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ In the given formula let 10 represents a and 4 represents b. $10^{2}$ - $4^{2}$ = (10+4)(10-4) = (10+4)(10-4) = (14)(6)
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