Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 28

Answer

(k+8)(k-8)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $(k)^{2}$ - 64 *** Take the square root of 64 which is 8. Becuase 8 × 8= 64 = $(k)^{2}−8^{2}$ In the given formula let k represents a and 8 represents b. $(k)^{2}−8^{2}$ = (k+8)(k-8)
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