Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 33

Answer

(8q+9)(8q-9)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $64q^{2}$ - 81 *** Take the square root of $64q^{2}$ which is 8q. Becuase 8q × 8q= $64q^{2}$ *** Take the square root of 81 which is 9. Becuase 9 × 9= 81 = $(8q)^{2}−9^{2}$ In the given formula let 8q represents a and 9 represents b. $(8q)^{2}−9^{2}$ = (8q+9)(8q-9)
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