Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 515: 32



Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $36v^{2}$ - 25 *** Take the square root of $36v^{2}$ which is 6v. Becuase 6v × 6v= $36v^{2}$ *** Take the square root of 25 which is 5. Becuase 5 × 5= 25 = $(6v)^{2}−5^{2}$ In the given formula let 6v represents a and 5 represents b. $(6v)^{2}−5^{2}$ = (6v+5)(6v-5)
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