Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 515: 39



Work Step by Step

Given the polynomial $27x^{2}$ + 90x + 75 We see that all three terms have a common factor of 3, so we factor out the 3. 3($9x^{2}$ + 90x + 25) We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ 3($(3x)^{2}$ + 90x + $5^{2}$) In this polynomial a= 3x and b=5 3($3x^{2}$ + 90x + $5^{2}$) = $3((3x+5)^{2}$)
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