## Algebra 1

$3((3x+5)^{2}$)
Given the polynomial $27x^{2}$ + 90x + 75 We see that all three terms have a common factor of 3, so we factor out the 3. 3($9x^{2}$ + 90x + 25) We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ 3($(3x)^{2}$ + 90x + $5^{2}$) In this polynomial a= 3x and b=5 3($3x^{2}$ + 90x + $5^{2}$) = $3((3x+5)^{2}$)