Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 515: 36



Work Step by Step

$2h^{2}$ - 2 We see that both the terms have a two common thus we factor it out. 2($h^{2}$ - 1) We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = 2($h^{2}$ - 1) *** Take the square root of $h^{2}$ which is h. Becuase h × h= $h^{2}$ *** Take the square root of 1 which is 1. Becuase 1 × 1= 1 = 2($(h)^{2}−1^{2}$) In the given formula let h represents a and 1 represents b. 2($(h)^{2}−1^{2}$) = 2(h+1)(h-1)
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