Answer
(4x+11)(4x-11)
Work Step by Step
We use the formula for the difference of squares to apply to this question.
The difference of squares formula is:
$(a-b) (a+b) = a^{2} - b^{2}$
= $16x^{2}$ - 121
*** Take the square root of $16x^{2}$ which is 9r. Becuase 4x × 4x= $16x^{2}$
*** Take the square root of 121 which is 11. Becuase 11 × 11= 121
= $(4x)^{2}−11^{2}$
In the given formula let 4x represents a and 11 represents b.
$(4x)^{2}−11^{2}$ = (4x+11)(4x-11)
