Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 31

Answer

(9r+1)(9r-1)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $81r^{2}$ - 1 *** Take the square root of $81r^{2}$ which is 9r. Becuase 9r × 9r= $81r^{2}$ *** Take the square root of 1 which is 1. Becuase 1 × 1= 1 = $(9r)^{2}−1^{2}$ In the given formula let 9r represents a and 1 represents b. $(9r)^{2}−1^{2}$ = (9r+1)(9r-1)
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