Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 27

Answer

(t+5)(t-5)

Work Step by Step

We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = $(t)^{2}$ - 25 *** Take the square root of 25 which is 5. Becuase 5 × 5= 25 = $(t)^{2}−5^{2}$ In the given formula let t represents a and 5 represents b. $(t)^{2}−5^{2}$ = (t+5)(t-5)
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