Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 45

Answer

(13)(11)

Work Step by Step

Given the number 143 we find two numbers that are perfect squares that add to give 143. We get +144 and -1 144 - 1 *** Take the square root of 144 which is 12. Becuase 12 × 12= 144 *** Take the square root of 1 which is 1. Becuase 1 × 1= 1 We rewrite it as the squares. $12^{2}$ - $1^{2}$ We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ In the given formula let 12 represents a and 1 represents b. $(12)^{2}−1^{2}$ = (12+1)(12-1) = (12+1)(12-1) = (13)(11)
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