Answer
5(4g+3)(4g-3)
Work Step by Step
$80g^{2}$ - 45
We see that both the terms have a 5 common thus we factor a 5 out.
5($16g^{2}$ - 9)
We use the formula for the difference of squares to apply to this question.
The difference of squares formula is:
$(a-b) (a+b) = a^{2} - b^{2}$
= 5($16g^{2}$ - 9)
*** Take the square root of $16g^{2}$ which is 4g. Becuase 4g × 4g= $16g^{2}$
*** Take the square root of 9 which is 3. Becuase 3 × 3= 9
= 5($(4g)^{2}−3^{2}$)
In the given formula let 4g represents a and 3 represents b.
5($(4g)^{2}−3^{2}$) = 5(4g+3)(4g-3)
