## Algebra 1

$27w^{2}$ - 12 We see that both the terms have a 3 common thus we factor a 3 out. 3($9w^{2}$ - 4) We use the formula for the difference of squares to apply to this question. The difference of squares formula is: $(a-b) (a+b) = a^{2} - b^{2}$ = 3($9w^{2}$ - 4) *** Take the square root of $9w^{2}$ which is 3w. Becuase 3w × 3w= $9w^{2}$ *** Take the square root of 4 which is 2. Becuase 2 × 2= 4 = 3($(3w)^{2}−2^{2}$) In the given formula let 3w represents a and 2 represents b. 3($(3w)^{2}−2^{2}$) = 3(3w+2)(3w-2)