Answer
3(3w+2)(3w-2)
Work Step by Step
$27w^{2}$ - 12
We see that both the terms have a 3 common thus we factor a 3 out.
3($9w^{2}$ - 4)
We use the formula for the difference of squares to apply to this question.
The difference of squares formula is:
$(a-b) (a+b) = a^{2} - b^{2}$
= 3($9w^{2}$ - 4)
*** Take the square root of $9w^{2}$ which is 3w. Becuase 3w × 3w= $9w^{2}$
*** Take the square root of 4 which is 2. Becuase 2 × 2= 4
= 3($(3w)^{2}−2^{2}$)
In the given formula let 3w represents a and 2 represents b.
3($(3w)^{2}−2^{2}$) = 3(3w+2)(3w-2)
