Answer
$2(2p+7)^{2}$
Work Step by Step
Given the polynomial
$8p^{2}$ + 56p + 98
We see that all three terms have a common factor of 2, so we factor out the 2.
$2(4p^{2} + 28p + 49)$
We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of
$a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$
2($(2p)^{2}$ + 28p + $7^{2}$)
In this polynomial a= 2p and b=7
2($(2p)^{2}$ + 28p + $7^{2}$) = $2(2p+7)^{2}$
