Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 515: 40



Work Step by Step

Given the polynomial $8p^{2}$ + 56p + 98 We see that all three terms have a common factor of 2, so we factor out the 2. $2(4p^{2} + 28p + 49)$ We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ 2($(2p)^{2}$ + 28p + $7^{2}$) In this polynomial a= 2p and b=7 2($(2p)^{2}$ + 28p + $7^{2}$) = $2(2p+7)^{2}$
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