Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 84

Answer

$z^3-9z^2+27z-27$

Work Step by Step

Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ or the cube of a binomial, the given expression, $ (z-3)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (z)^3+3(z)^2(-3)+3(z)(-3)^2+(-3)^3 \\\\= z^3+3z^2(-3)+3z(9)+(-27) \\\\= z^3-9z^2+27z-27 .\end{array}
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