Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 77

Answer

$4a^2+4ab+b^2-12a-6b+9$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ [(2a+b)-3]^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (2a+b)^2+2(2a+b)(-3)+(-3)^2 \\\\= (2a+b)^2-6(2a+b)+9 \\\\= (2a+b)^2-12a-6b+9 \\\\= [(2a)^2+2(2a)(b)+(b)^2]-12a-6b+9 \\\\= 4a^2+4ab+b^2-12a-6b+9 .\end{array}
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