Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 53

Answer

$16m^{2}-49n^{4}$

Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $(4m+7n^{2})(4m-7n^{2})=(4m)^{2}-(7n^{2})^{2}=4^{2}m^{2}-7^{2}(n^{2})^{2}=16m^{2}-49n^{4}$.
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