Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 85

Answer

$125r^3-150r^2+60r-8$

Work Step by Step

Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ or the cube of a binomial, the given expression, $ (5r-2)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (5r)^3+3(5r)^2(-2)+3(5r)(-2)^2+(-2)^3 \\\\= 125r^3+3(25r^2)(-2)+3(5r)(4)+(-8) \\\\= 125r^3-150r^2+60r-8 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.