Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 78

Answer

$16k^2+8hk+h^2-32k-8h+16$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ [(4k+h)-4]^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (4k+h)^2+2(4k+h)(-4)+(-4)^2 \\\\= (4k+h)^2-8(4k+h)+16 \\\\= (4k+h)^2-32k-8h+16 \\\\= [(4k)^2+2(4k)(h)+(h)^2]-32k-8h+16 \\\\= 16k^2+8hk+h^2-32k-8h+16 .\end{array}
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