Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 83

Answer

$y^3+6y^2+12y+8$

Work Step by Step

Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ or the cube of a binomial, the given expression, $ (y+2)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (y)^3+3(y)^2(2)+3(y)(2)^2+(2)^3 \\\\= y^3+6y^2+12y+8 .\end{array}
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