## Intermediate Algebra (12th Edition)

$y^3+6y^2+12y+8$
Using $(a+b)^3=a^3+3a^2b+3ab^2+b^3$ or the cube of a binomial, the given expression, $(y+2)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (y)^3+3(y)^2(2)+3(y)(2)^2+(2)^3 \\\\= y^3+6y^2+12y+8 .\end{array}