Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 63

Answer

$16n^{2}-24nm+9m^{2}$

Work Step by Step

From Page 302, we know that the square of a binomial difference $x-y$ is given by the following equation: $(x-y)^{2}=x^{2}-2xy+y^{2}$ Therefore, $(4n-3m)^{2}=(4n)^{2}-2(4n)(3m)+(3m)^{2}=4^{2}n^{2}-24nm+3^{2}m^{2}=16n^{2}-24nm+9m^{2}$.
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