Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 55

Answer

$75y^{7}-12y^{2}$

Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $3y(5y^{3}+2)(5y^{3}-2)=3y((5y^{3})^{2}-2^{2})=3y(5^{2}(y^{3})^{2}-4)=3y(25y^{6}-4y)=75y^{7}-12y^{2}$.
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