## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 54

#### Answer

$4k^{4}-36h^{2}$

#### Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $(2k^{2}+6h)(2k^{2}-6h)=(2k^{2})^{2}-(6h)^{2}=2^{2}(k^{2})^{2}-6^{2}h^{2}=4k^{4}-36h^{2}$.

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