Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 69

Answer

$16x^2-\dfrac{4}{9}$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $ \left(4x-\dfrac{2}{3}\right)\left(4x+\dfrac{2}{3}\right) ,$ is equivalent to \begin{array}{l}\require{cancel} (4x)^2-\left(\dfrac{2}{3}\right)^2 \\\\= 16x^2-\dfrac{4}{9} .\end{array}
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