Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 70

Answer

$9t^2-\dfrac{25}{16}$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $ \left(3t-\dfrac{5}{4}\right)\left(3t+\dfrac{5}{4}\right) ,$ is equivalent to \begin{array}{l}\require{cancel} (3t)^2-\left(\dfrac{5}{4}\right)^2 \\\\= 9t^2-\dfrac{25}{16} .\end{array}
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