Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 56

Answer

$36x^{7}-64x$

Work Step by Step

From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$. Therefore, $4x(3x^{3}+4)(3x^{3}-4)=4x((3x^{3})^{2}-4^{2})=4x(3^{2}(x^{3})^{2}-16)=4x(9x^{6}-16)=36x^{7}-64x$.
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