Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 89

Answer

$6a^3+7a^2b+4ab^2+b^3$

Work Step by Step

Using the Distributive Property, the given expression, $ (2a+b)(3a^2+2ab+b^2) ,$ is equivalent to \begin{array}{l}\require{cancel} 2a(3a^2)+2a(2ab)+2a(b^2)+b(3a^2)+b(2ab)+b(b^2) \\\\= 6a^3+4a^2b+2ab^2+3a^2b+2ab^2+b^3 \\\\= 6a^3+(4a^2b+3a^2b)+(2ab^2+2ab^2)+b^3 \\\\= 6a^3+7a^2b+4ab^2+b^3 .\end{array}
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