Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 97

Answer

The solution below shows that $(x+y)^2$ is not equal to $x^2+y^2.$

Work Step by Step

Substituting $x=3$ and $y=4,$ the given expression, $ (x+y)^2 ,$ evaluates to \begin{array}{l}\require{cancel} (3+4)^2 \\\\= (7)^2 \\\\= 49 ,\end{array} while the given expression, $ x^2+y^2 ,$ evaluates to \begin{array}{l}\require{cancel} 3^2+4^2 \\\\= 9+16 \\\\= 25 .\end{array}
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