Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 65

Answer

$k^2-\dfrac{10}{7}kp+\dfrac{25}{49}p^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( k-\dfrac{5}{7}p \right)^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (k)^2+2(k)\left(-\dfrac{5}{7}p\right)+\left(-\dfrac{5}{7}p\right)^2 \\\\= k^2-\dfrac{10}{7}kp+\dfrac{25}{49}p^2 .\end{array}
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