Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises: 66

Answer

$q^2-\dfrac{3}{2}qr+\dfrac{9}{16}r^2$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the given expression, $ \left( q-\dfrac{3}{4}r \right)^2 ,$ is equivalent to \begin{array}{l}\require{cancel} (q)^2+2(q)\left(-\dfrac{3}{4}r\right)+\left(-\dfrac{3}{4}r\right)^2 \\\\= q^2-\dfrac{3}{2}qr+\dfrac{9}{16}r^2 .\end{array}
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