## Intermediate Algebra (12th Edition)

$A=(x^4+16x^2+64)\text{ square units}$
Using $A=s^2$, the area of the square with side measurement equal to $(x^2+8)$ is \begin{array}{l}\require{cancel} A=(x^2+8)^2 .\end{array} Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the expression above is equivalent to \begin{array}{l}\require{cancel} A=(x^2)^2+2(x^2)(8)+(8)^2 \\\\ A=x^4+16x^2+64 \\\\ A=(x^4+16x^2+64)\text{ square units} .\end{array}