Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 605: 27b

Answer

$|W|=1.49\times 10^4J$

Work Step by Step

As the efficiency is given as: $\epsilon=\frac{|W|}{|Q_H|}$ This can be rearranged as: $W=\epsilon|Q_H|$ We plug in the known values to obtain: $|W|=(0.236)(6.30\times 10^4)=1.49\times 10^4J$
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