Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 20 - Entropy and the Second Law of Thermodynamics - Problems - Page 605: 17c

Answer

$\frac{T_3}{T_1 } = 0.644$

Work Step by Step

To find the $T_3/T_1$ for the path $ 1 \rightarrow 2$, we need to use the equation $T_3 = T_1 (\frac{V_1}{V_3})^{\gamma -1 }$ Where $\gamma = \frac{7}{5}$ and $V_3 = 3.00V_1$ $\frac{T_3}{T_1 } = (\frac{V_1}{3.00V_1})^{7/5-1 }$ $\frac{T_3}{T_1 } = (\frac{1}{3.00})^{2/5}$ $\frac{T_3}{T_1 } = 0.644$
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